document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016172>Question 1016172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a school is building a rectangle soccer field that has an area of 6000 square yards. the soccer field must be 40 yards longer than its width. determine algebraically the dimensions of the soccer field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632591 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "W=width; L=length=W+40yds<BR>\n" );
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document.write( "LW=6000yd^2<BR>\n" );
document.write( "(W+40yd)(W)=6000yd^2<BR>\n" );
document.write( "W^2+40W=6000<BR>\n" );
document.write( "W^2+40W-6000=0 <BR>\n" );
document.write( "(W-60)(W+100)=0<BR>\n" );
document.write( "W-60=0 -OR- W+100=0<BR>\n" );
document.write( "W=60 -OR- W=-100<BR>\n" );
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document.write( "ANSWER 1: The width is 60 yards.<BR>\n" );
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document.write( "L=W+40yds-60yds+40yds=100yds<BR>\n" );
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document.write( "ANSWER 2: The length is 100 yards.<BR>\n" );
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