document.write( "Question 1013524: Roger has $3.15 in quarters dimes and nickels he has twice as many quarters as dimes and two more dimes than nickels. how many of each kind are there? \n" ); document.write( "
Algebra.Com's Answer #632583 by FrankM(1040)\"\" \"About 
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5N+10D+25Q=315 << We mutiply the number of Nickels (N) by its value 5, to get the value of all nickels, 10 for dimes, 25 for quarters. \r
\n" ); document.write( "\n" ); document.write( "Q=2D\r
\n" ); document.write( "\n" ); document.write( "D=N+2 \r
\n" ); document.write( "\n" ); document.write( "Now, 3 equations, in 3 unknowns. \r
\n" ); document.write( "\n" ); document.write( "Since Q=2D, Q=2(N+2)\r
\n" ); document.write( "\n" ); document.write( "5N+10(N+2)+25(2(N+2))=315 \r
\n" ); document.write( "\n" ); document.write( "5N+10N+20+50N+100=315\r
\n" ); document.write( "\n" ); document.write( "65N+120=315\r
\n" ); document.write( "\n" ); document.write( "65N=195\r
\n" ); document.write( "\n" ); document.write( "N=3, D=5, Q=10\r
\n" ); document.write( "\n" ); document.write( "Check -\r
\n" ); document.write( "\n" ); document.write( "5*3+10*5+25*10=315\r
\n" ); document.write( "\n" ); document.write( "15+50+250 = 315
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