document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016162>Question 1016162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> B is inversely proportional to a. If b=9 when a=3, find b when a=3/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632564 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  B is inversely proportional to a. If b=9 when a=3, find b when a=3/2 <BR>\n" );
document.write( "-----<BR>\n" );
document.write( "B = k/a<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Solve for k using \"B = 9 when a = 3\"::<BR>\n" );
document.write( "9 = k/3<BR>\n" );
document.write( "k = 27<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "B = 27/a<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Now, find B when a = 3/2::<BR>\n" );
document.write( "B = 27/(3/2)<BR>\n" );
document.write( "B = 18<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );