document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016153>Question 1016153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measures of two complementary angles are in the ratio 4:1. What is the measure of the smaller angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632545 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "S=smaller angle; L=larger angle=4S<BR>\n" );
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document.write( "S+L=90<BR>\n" );
document.write( "S+4S=90<BR>\n" );
document.write( "5S=90<BR>\n" );
document.write( "S=18<BR>\n" );
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document.write( "ANSWER: The measure of the smaller angle is 18 degrees.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
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document.write( "L=4S=4(18)=72<BR>\n" );
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document.write( "L+S=90<BR>\n" );
document.write( "72+18=90<BR>\n" );
document.write( "90=90<BR>\n" );
document.write( ".<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );