document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016132>Question 1016132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this question\r<BR>\n" );
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document.write( "A hemispherical tank full of water is emptied by a pipe at the rate of 25/7 litres per second. How much time will it take to empty half the tank, if it is 3m in diameter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632526 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A hemispherical tank full of water is emptied by a pipe at the rate of 25/7 litres per second. How much time will it take to empty half the tank, if it is 3m in diameter<BR>\n" );
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document.write( "r = 1.5 meters<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+4pi%2Ar%5E3%2F3 ALIGN=MIDDLE  ALT=\"Vol+=+4pi%2Ar%5E3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%5E3%2F3 ALIGN=MIDDLE  ALT=\"2pi%2Ar%5E3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > for 1/2 the sphere.<BR>\n" );
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document.write( "\"1/2 the tank\" is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E3%2F3 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Using 1.5 meters gives cubic meters.<BR>\n" );
document.write( "1 cubic meter = 1000 liters<BR>\n" );
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document.write( "time = liters/(liters/sec) in seconds\r<BR>\n" );
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