document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87324>Question 87324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In Problem 64, you’re essentially solving a problem like Example 9 (p 556).  Use one ordered pair to find k, and then use that value along with the other given value to determine what its corresponding ordered pair will be.\r<BR>\n" );
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document.write( "64) Business and finance.  The revenue for a sandwich shop is directly proportional to its advertising budget.  When the owner spent $2000 a month on advertising, the revenue was $120,000.  If the revenue is now $180,000, how much is the owner spending on advertising?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63250 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the formula for direct variation:<BR>\n" );
document.write( "y=xk [plug-in the values]<BR>\n" );
document.write( "$120,000 = $2000k [solve for the k-term]<BR>\n" );
document.write( "120,000/2000=k<BR>\n" );
document.write( "60=k<BR>\n" );
document.write( "So, the formula becomes:<BR>\n" );
document.write( "y=60x<BR>\n" );
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document.write( "If the revenue is now $180,000, how much is the owner spending on advertising? \r<BR>\n" );
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document.write( "Using y=60x [plug-in the values and solve for advertisment (x)]<BR>\n" );
document.write( "($180,000) = 60x<BR>\n" );
document.write( "180,000/60=60/x<BR>\n" );
document.write( "$3,000 = x (amont spent on advertisment)<BR>\n" );
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