document.write( "Question 1015872: Six times the smallest of three consecutive odd integers is 28 more than twice the largest. Find the integers \n" ); document.write( "

Algebra.Com's Answer #632499 by macston(5194) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "S=smallest integer; M=middle integer=S+2; L=largest integer=S+4
\n" ); document.write( ".
\n" ); document.write( "6S=2L+28
\n" ); document.write( "6S=2(S+4)+28
\n" ); document.write( "6S=2S+8+28
\n" ); document.write( "6S=2S+36
\n" ); document.write( "4S=36
\n" ); document.write( "S=9
\n" ); document.write( ".
\n" ); document.write( "M=S+2=9+2=11
\n" ); document.write( ".
\n" ); document.write( "L=S+4=9+4=13
\n" ); document.write( ".
\n" ); document.write( "ANSWER: The three integers are 9,11, and 13.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "6S=2L+28
\n" ); document.write( "6(9)=2(13)+28
\n" ); document.write( "54=26+28
\n" ); document.write( "54=54
\n" ); document.write( ".
\n" ); document.write( " \n" ); document.write( "

\n" );