document.write( "Question 1015984: Two years ago a woman was 4 times as old as her daughter. Three years from now the mother will be only three times as old as her daughter. How old are each of them now? \n" ); document.write( "
Algebra.Com's Answer #632487 by macston(5194)\"\" \"About 
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\n" ); document.write( "M=mother's age; D=daughter's age
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\n" ); document.write( "M-2=4(D-2)
\n" ); document.write( "M-2=4D-8
\n" ); document.write( "M=4D-6
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\n" ); document.write( "M+3=3(D+3)
\n" ); document.write( "M+3=3D+9
\n" ); document.write( "M=3D+6
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\n" ); document.write( "4D-6=3D+6
\n" ); document.write( "D-6=6
\n" ); document.write( "D=12
\n" ); document.write( "ANSWER 1: Daughter is 12 years old.
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\n" ); document.write( "M=4D-6=4(12)-6=48-6=42
\n" ); document.write( "ANSWER 2: Mother is 42 years old.
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\n" ); document.write( "CHECK:
\n" ); document.write( "M+3=3(D+3)
\n" ); document.write( "42+3=3(12+3)
\n" ); document.write( "45=3(15)
\n" ); document.write( "45=45
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