document.write( "Question 1015984: Two years ago a woman was 4 times as old as her daughter. Three years from now the mother will be only three times as old as her daughter. How old are each of them now? \n" ); document.write( "
Algebra.Com's Answer #632487 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "M=mother's age; D=daughter's age \n" ); document.write( ". \n" ); document.write( "M-2=4(D-2) \n" ); document.write( "M-2=4D-8 \n" ); document.write( "M=4D-6 \n" ); document.write( ". \n" ); document.write( "M+3=3(D+3) \n" ); document.write( "M+3=3D+9 \n" ); document.write( "M=3D+6 \n" ); document.write( ". \n" ); document.write( "4D-6=3D+6 \n" ); document.write( "D-6=6 \n" ); document.write( "D=12 \n" ); document.write( "ANSWER 1: Daughter is 12 years old. \n" ); document.write( ". \n" ); document.write( "M=4D-6=4(12)-6=48-6=42 \n" ); document.write( "ANSWER 2: Mother is 42 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "M+3=3(D+3) \n" ); document.write( "42+3=3(12+3) \n" ); document.write( "45=3(15) \n" ); document.write( "45=45 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |