document.write( "Question 1016090: sam bought two books.one book cost 4.00$ more than three times other.together,the two books cost him 72$ \n" ); document.write( "
Algebra.Com's Answer #632442 by macston(5194)\"\" \"About 
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\n" ); document.write( "X=cost of book 1; Y=cost of book 2=3X+$4.00
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\n" ); document.write( "X+Y=$72 . Substitute (3X+$4) for Y.
\n" ); document.write( "X+(3X+$4)=$72
\n" ); document.write( "4X=$68
\n" ); document.write( "X=$17
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\n" ); document.write( "ANSWER 1: Book 1 cost $17.
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\n" ); document.write( "Y=3X+$4=3($17)+$4=$51+$4=$55
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\n" ); document.write( "ANSWER 2: Book 2 cost $55.
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\n" ); document.write( "CHECK:
\n" ); document.write( "X+Y=$72
\n" ); document.write( "$17+$55=$72
\n" ); document.write( "$72=$72
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