document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015944>Question 1015944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 840, find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632339 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the first number, x.<BR>\n" );
document.write( "The second would be 8x.<BR>\n" );
document.write( "The third would be x + 100.<BR>\n" );
document.write( "Adding them we get<BR>\n" );
document.write( "x + 8x + x+100 = 840<BR>\n" );
document.write( "10x + 100 = 840<BR>\n" );
document.write( "10x = 740<BR>\n" );
document.write( "x = 74<BR>\n" );
document.write( "8x = 592<BR>\n" );
document.write( "x+100 = 174 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );