document.write( "Question 1015938: from the following two equations:\r
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document.write( "3a-2b=11
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document.write( "5a+7b=39\r
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document.write( "find a and b \n" );
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Algebra.Com's Answer #632320 by FrankM(1040)![]() ![]() You can put this solution on YOUR website! 3a-2b=11 \n" ); document.write( "5a+7b=39\r \n" ); document.write( "\n" ); document.write( "multiply 1st equation by 5 and second by 3.\r \n" ); document.write( "\n" ); document.write( "15a-10b=55 \n" ); document.write( "15a+21b=117\r \n" ); document.write( "\n" ); document.write( "flip signs on first equation and add - \r \n" ); document.write( "\n" ); document.write( "-15a+10b=-55 \n" ); document.write( "15a+21b=117 \n" ); document.write( "____________________\r \n" ); document.write( "\n" ); document.write( "31B = 62\r \n" ); document.write( "\n" ); document.write( "B=2\r \n" ); document.write( "\n" ); document.write( "3A-2(2)=11\r \n" ); document.write( "\n" ); document.write( "3A-4=11\r \n" ); document.write( "\n" ); document.write( "3A=15\r \n" ); document.write( "\n" ); document.write( "A=5 \n" ); document.write( " |