document.write( "Question 1015880: Consider the logarithmic equation f(x) = ln (x + 2) – 1. Round all values to the tenths place.
\n" ); document.write( "(a) Determine any x- and y-intercepts.
\n" ); document.write( "(b) Determine the domain and the equation of the vertical asymptote.
\n" ); document.write( "(c) Make a table of values to find three other points on the graph.
\n" ); document.write( "(d) Graph the function. Label the three points you found in Part (c). \n" ); document.write( "

Algebra.Com's Answer #632298 by Boreal(15235) $\"\"$ $\"About$

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ln(x+2)-1
\n" ); document.write( "x must be greater than -2.
\n" ); document.write( "As x approaches -2, ln (x+2) gets more and more negative, so x=-2 is vertical asymptote. When x=0, y=ln(2)-1, =-0.3
\n" ); document.write( "when y=0,
\n" ); document.write( "ln(x+2)=1 and raising both to the e power, (x+2)=2.7 and x=0.7
\n" ); document.write( "ln(1)=0, therefore x=-1, y=-1
\n" ); document.write( "Table
\n" ); document.write( "0,-0.3
\n" ); document.write( "0.7,0
\n" ); document.write( "-1,-1
\n" ); document.write( " $\"graph%28300%2C200%2C-3%2C2%2C-5%2C1%2Cln%28x%2B2%29-1%29\"$
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