document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015897>Question 1015897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Martha can rake the leaves in her yard in 5 hours. Her brother can do the job in 3 hours. How long will it take them to do the job working together? answer in fraction an hr<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632281 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In an hour, Martha does 1/5 of the yard.<BR>\n" );
document.write( "In an hour, her brother does 1/3 of the yard.<BR>\n" );
document.write( "together, they do (1/5)+(1/3) of the yard every hour or (8/15) of the yard (adding the two with common denominator of 15).<BR>\n" );
document.write( "It takes 15/8 hours for both of them to do it.<BR>\n" );
document.write( "(1/5)+(1/3)=(1/x)<BR>\n" );
document.write( "multiply everything by 15x<BR>\n" );
document.write( "3x+5x=15<BR>\n" );
document.write( "x=(15/8)<BR>\n" );
document.write( "Check.<BR>\n" );
document.write( "She does 20% of the yard in an hour.  He does 33%.  It will take between 1 and 2 hours, closer to 2.<BR>\n" );
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