document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015898>Question 1015898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many quarts of pure antifreeze must be added to 6 quarts of a 20% antifreeze solution to obtain a 40% antifreeze solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632276 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> pure antifreeze=x qts.<BR>\n" );
document.write( "(6+x)*0.40=6*0.20+x<BR>\n" );
document.write( "2.40+0.40x=1.2+x<BR>\n" );
document.write( "1.20=0.6x<BR>\n" );
document.write( "x=2 qts.<BR>\n" );
document.write( "What you want to equalize is the amount of pure antifreeze in both sides of the equation.<BR>\n" );
document.write( "you start with 1.2 (6*0.2) qts.<BR>\n" );
document.write( "you are adding x qts to 6.<BR>\n" );
document.write( "you are ending up with (6+x) qts of 40% or 0.4<BR>\n" );
document.write( "8 qts of 0.4=3.2 qts of pure<BR>\n" );
document.write( "You start with 6 qts. and end up with 8.<BR>\n" );
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