document.write( "Question 1015879: The length of a rectangle is 4 inches more than its width. If 2 inches are taken from the length and added to the width, the figure becomes a square with an area of 361 square inches. \n" ); document.write( "

Algebra.Com's Answer #632268 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "What is your question?
\n" ); document.write( ".
\n" ); document.write( "For a square:
\n" ); document.write( "Area =(side)^2
\n" ); document.write( " $\"361in%5E2=%28side%29%5E2\"$
\n" ); document.write( " $\"sqrt%28361in%5E2%29=sqrt%28side%5E2%29\"$
\n" ); document.write( " $\"19in=side\"$
\n" ); document.write( ".
\n" ); document.write( "The sides of the square are 19 inches
\n" ); document.write( "Subtract 2 inches from one side and add to adjacent side:
\n" ); document.write( "Dimensions of the rectangle were
\n" ); document.write( "(19-2) x (19+2) = 17 x 21
\n" ); document.write( "The rectangle was 17 in by 21 in.\r
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