document.write( "Question 87119: 2x - y + 2z = -8
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document.write( "-x + 3y - 4z = 15
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document.write( " x + 2y - 3z = 9
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Algebra.Com's Answer #63225 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "2x - y + 2z = -8\r\n" ); document.write( "-x + 3y - 4z = 15\r\n" ); document.write( " x + 2y - 3z = 9\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 2 | -8]\r\n" ); document.write( "[-1 3 -4 | 15]\r\n" ); document.write( "[ 1 2 -3 | 9] \r\n" ); document.write( "\r\n" ); document.write( "Get a zero where the -1 is on the 2nd row is by\r\n" ); document.write( "multiplying the first row by 1 and adding it\r\n" ); document.write( "to 2 times the second row:\r\n" ); document.write( "\r\n" ); document.write( "1[ 2 -1 2 | -8]\r\n" ); document.write( "2[-1 3 -4 | 15]\r\n" ); document.write( " [ 1 2 -3 | 9]\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 2 | -8]\r\n" ); document.write( "[ 0 5 -6 | 22]\r\n" ); document.write( "[ 1 2 -3 | 9]\r\n" ); document.write( "\r\n" ); document.write( "Get a zero where the 1 is on the 3rd row is by\r\n" ); document.write( "multiplying the first row by 1 and adding it\r\n" ); document.write( "to -2 times the third row: \r\n" ); document.write( "\r\n" ); document.write( " 1[ 2 -1 2 | -8]\r\n" ); document.write( " [ 0 5 -6 | 22]\r\n" ); document.write( "-2[ 1 2 -3 | 9]\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 2 | -8]\r\n" ); document.write( "[ 0 5 -6 | 22]\r\n" ); document.write( "[ 0 -5 8 |-26]\r\n" ); document.write( "\r\n" ); document.write( "Get a 0 where the -5 is on the third row by\r\n" ); document.write( "multiplying the second row by 1 and adding it\r\n" ); document.write( "to 1 times row 3:\r\n" ); document.write( "\r\n" ); document.write( " [ 2 -1 2 | -8]\r\n" ); document.write( "1[ 0 5 -6 | 22]\r\n" ); document.write( "1[ 0 -5 8 |-26]\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 2 | -8]\r\n" ); document.write( "[ 0 5 -6 | 22]\r\n" ); document.write( "[ 0 0 2 | -4]\r\n" ); document.write( "\r\n" ); document.write( "-1,2,-2\r\n" ); document.write( "\r\n" ); document.write( "Get a 1 where the 2 is in the first row by\r\n" ); document.write( "dividing the first row through by 2\r\n" ); document.write( "\r\n" ); document.write( "Get a 1 where the 5 is in the second row by\r\n" ); document.write( "dividing the second row through by 5\r\n" ); document.write( "\r\n" ); document.write( "Get a 1 where the 2 is in the third row by\r\n" ); document.write( "dividing the third row through by 2\r\n" ); document.write( "\r\n" ); document.write( "[ 1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |