document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015853>Question 1015853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you graph y=-2x+2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632232 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632232\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=FrankM&illustration_name=Screen_shot_2016_01_26_at_9.05.26_AM.png\">\r<BR>\n" );
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document.write( "Your equation is great. It's in the form y=mx+b  where m is the slope and b is the y intercept. \r<BR>\n" );
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document.write( "The first point we draw is (0,2), it's on the Y axis, note that on the Y axis, X is zero. Next we look at the slope, -2.  Slope is thought or as \"rise over run\" so in this case we go down 2 and right 1. We land on (1,0) and draw that second point. A nice straightedge, and draw the rest of your line. \r<BR>\n" );
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