document.write( "Question 1015843: Find the equation of a circle passing through (-1,6) and tangent to the lines x-2y+8=0 and 2x+y+6=0. \n" ); document.write( "

Algebra.Com's Answer #632225 by FrankM(1040) $\"\"$ $\"About$

You can put this solution on YOUR website!
There is no solution. Please see this graph. \r
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\n" ); document.write( "\n" ); document.write( "The red line is the equation x-2y+8=0. The point (-1,6) forms a perpendicular line to it at (0,4) which is $\"sqrt%285%29\"$ away. \r
\n" ); document.write( "\n" ); document.write( "The circle equation is $\"%28x%2B1%29%5E2%2B%28y-6%29%5E2=5\"$ but as you see, it's tangent to the one line, not both at once. \r
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