document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014080>Question 1014080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the volume and the altitude of a certain pyramidal pile whose base is an equilateral triangle are 10 cubic meters and 2 meters find the side of the base of the pile </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632190 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \frac{1}{3} \times A \times 2 = 10\"> where A is the area of the base (in m^2), so A = 15 m^2.\r<BR>\n" );
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document.write( "Using the area of an equilateral triangle, we have <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \frac{s^2 \sqrt{3}}{4} = 15\">. Solving, <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large s^2 = 20 \sqrt{3}\"> or <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large s = \sqrt{20 \sqrt{3}}\">. </SPAN>\n" );
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