document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015788>Question 1015788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pablos coffee shop makes a blend of coffee that is a mixture of two types of coffee. type A coffee cpst pablo $5.50 per pound, and type B coffee costs $4.30 per pound. this month, pavlo made 127 pounds of the blend, for a total cost of $607.30. how many pounds of type A coffee did he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632156 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+B= 127 subtract B from both sides: <BR>\n" );
document.write( "A= 127-B We'll use this value for A next.<BR>\n" );
document.write( "5.50A+4.30B = 607.30 Now substitute for A:<BR>\n" );
document.write( "5.50(127-B)+4.30B = 607.30<BR>\n" );
document.write( "698.5-5.50B+4.30B = 607.30 Now subtract 698.5 from both sides and subtract B on left:<BR>\n" );
document.write( "-1.2B = -91.20 Now divide both sides by -1.2 (and remember: -/- = +)<BR>\n" );
document.write( "B = 76 pounds. And:<BR>\n" );
document.write( "127-76 = 51 pounds are type A<BR>\n" );
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