document.write( "Question 1015739: Let line l1 be the graph of 5x + 8y = -9. Line l2 is perpendicular to line l1 and passes through the point (10,10). If line l2 is the graph of the equation y=mx +b, then find m+b. \n" ); document.write( "
Algebra.Com's Answer #632143 by macston(5194)\"\" \"About 
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Find slope of first line (slope-intercept form):
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\n" ); document.write( "5x+8y=-9
\n" ); document.write( "8y=-5x-9
\n" ); document.write( "y=-(5/8)x+(9/8)
\n" ); document.write( "m=-5/8
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\n" ); document.write( "Slope of perpendicular line is negative reciprocal of original.
\n" ); document.write( "Slope line 12=m=8/5
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\n" ); document.write( "In slope intercept form:
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=(8/5)x+b
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\n" ); document.write( "To find b, use given point (10,10)
\n" ); document.write( "x=10; y=10
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\n" ); document.write( "y=(8/5)x+b
\n" ); document.write( "10=(8/5)(10)+b
\n" ); document.write( "10=(80/5)+b
\n" ); document.write( "10=16+b
\n" ); document.write( "-6=b
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\n" ); document.write( "ANSWER: m=8/5; b=-6; m+b=-22/5
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