document.write( "Question 1015739: Let line l1 be the graph of 5x + 8y = -9. Line l2 is perpendicular to line l1 and passes through the point (10,10). If line l2 is the graph of the equation y=mx +b, then find m+b. \n" ); document.write( "
Algebra.Com's Answer #632143 by macston(5194) You can put this solution on YOUR website! Find slope of first line (slope-intercept form): \n" ); document.write( ". \n" ); document.write( "5x+8y=-9 \n" ); document.write( "8y=-5x-9 \n" ); document.write( "y=-(5/8)x+(9/8) \n" ); document.write( "m=-5/8 \n" ); document.write( ". \n" ); document.write( "Slope of perpendicular line is negative reciprocal of original. \n" ); document.write( "Slope line 12=m=8/5 \n" ); document.write( ". \n" ); document.write( "In slope intercept form: \n" ); document.write( "y=mx+b \n" ); document.write( "y=(8/5)x+b \n" ); document.write( ". \n" ); document.write( "To find b, use given point (10,10) \n" ); document.write( "x=10; y=10 \n" ); document.write( ". \n" ); document.write( "y=(8/5)x+b \n" ); document.write( "10=(8/5)(10)+b \n" ); document.write( "10=(80/5)+b \n" ); document.write( "10=16+b \n" ); document.write( "-6=b \n" ); document.write( ". \n" ); document.write( "ANSWER: m=8/5; b=-6; m+b=-22/5 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |