document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015718>Question 1015718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 cm greater than twice the width. The area is 33 cm squared. find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632115 by </B><A HREF=/tutors/aboutme.mpl?userid=428225><B>428225(90)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=428225><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=428225><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you let x = the width of the triangle then the length = 2x+5<BR>\n" );
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document.write( "You know that the area is 33 therefore you need to multiply the width and length together.<BR>\n" );
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document.write( "x(2x+5)=33<BR>\n" );
document.write( "2x^2+5x-33=0\r<BR>\n" );
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document.write( "Solve this quadratic to find the answer (Remember that width and length cannot be negative).<BR>\n" );
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