document.write( "Question 1015672: five times the smallest of three consectutive integers is 17 less than twice the sum of the integers \n" ); document.write( "
Algebra.Com's Answer #632029 by macston(5194)\"\" \"About 
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You did not ask a question. I assume you want to know the integers.
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\n" ); document.write( "S=smallest integer; M=middle integer=S+1; L=largest integer=S+2
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\n" ); document.write( "5S=2(S+M+L)-17
\n" ); document.write( "5S=2(S+S+1+S+2)-17
\n" ); document.write( "5S=2(3S+3)-17
\n" ); document.write( "5S=6S+6-17
\n" ); document.write( "5S=6S-11
\n" ); document.write( "11=S
\n" ); document.write( "ANSWER 1: The smallest integer is 11.
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\n" ); document.write( "M=S+1=11+1=12
\n" ); document.write( "ANSWER 2: The middle integer is 12.
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\n" ); document.write( "L=S+2=11+2=13
\n" ); document.write( "ANSWER 3: The largest integer is 13.
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\n" ); document.write( "CHECK:
\n" ); document.write( "5S=2(S+M+L)-17
\n" ); document.write( "5(11)=2(11+12+13)-17
\n" ); document.write( "55=2(36)-17
\n" ); document.write( "55=72-17
\n" ); document.write( "55=55
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