document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015664>Question 1015664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello please help solve these few questions step by step.\r<BR>\n" );
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document.write( "Question 1: -9.1 - |-7.5|\r<BR>\n" );
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document.write( "Question 2: 4x2 + 2 when x = 2.\r<BR>\n" );
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document.write( "Question 3: (5 - x)/6 when x = 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632020 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632020\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -9.1 - |-7.5| =-9.1-7.5=-16.6. The absolute value is positive, but then it is subtracted.<BR>\n" );
document.write( "Question 2: 4x2 + 2 when x = 2. 4*(2)^2+2=18<BR>\n" );
document.write( "Question 3: (5 - x)/6 when x = 3. (5-3)/6=(2/6)=(1/3) </SPAN>\n" );
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