document.write( "Question 1015621: 1. Solve for A[0<_A<_90°]
\n" ); document.write( "TanA+Tan2A+Tan3A=0
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Algebra.Com's Answer #631994 by robertb(5830)\"\" \"About 
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tan A + tan2A + tan3A = 0\r
\n" ); document.write( "\n" ); document.write( "\"%28tanA+%2B+tan2A%29+%2B+%28tanA+%2B+tan2A%29%2F%281-tanA%2Atan2A%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28tanA+%2B+tan2A%29%2A%281+%2B+1%2F%281-tanA%2Atan2A%29%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "==>\"%28tanA+%2B+tan2A%29%2A%28%282+-+tanA%2Atan2A%29%2F%281-tanA%2Atan2A%29%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "==> tanA + tan2a = 0 OR \"%282+-+tanA%2Atan2A%29%2F%281-tanA%2Atan2A%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "The first case is equivalent to \"%28sinA%2Acos2A+%2B+sin2A%2AcosA%29%2F%28cosA%2Acos2A%29+=+0\", or equivalently, \"%28sin3A%29%2F%28cosA%2Acos2A%29+=+0\".
\n" ); document.write( "This happens only when 3A = 0, or A = 0 degree. (Notice A = 0 does not make the denominator 0, so A = 0 is a valid solution. It can be checked also by using the original equation that A = 0 is indeed a solution.)\r
\n" ); document.write( "\n" ); document.write( "The 2nd case \"%282+-+tanA%2Atan2A%29%2F%281-tanA%2Atan2A%29+=+0\" implies that
\n" ); document.write( "2 - tanA*tan2A = 0. (Notice that this effectively means that the denominator 1 - tanA*tan2A is not equal to 0.)\r
\n" ); document.write( "\n" ); document.write( "==> tanA*tan2A = 2
\n" ); document.write( "==> \"tanA%2A%28%282tanA%29%2F%281-%28tanA%29%5E2%29%29+=+2\" <==>\"%282%28tanA%29%5E2%29%2F%281-%28tanA%29%5E2%29+=+2\".
\n" ); document.write( "Now the only value of A that will make the denominator of the last equation 0 is 45 degrees, in which tanA = 1. Thus we exclude A = 45 degrees from the solution and
\n" ); document.write( "let \"2%28tanA%29%5E2+=+2-2%28tanA%29%5E2\", or\r
\n" ); document.write( "\n" ); document.write( "\"4%28tanA%29%5E2+=+2\", or \"%28tanA%29%5E2+=+1%2F2\".\r
\n" ); document.write( "\n" ); document.write( "==> \"tanA+=+1%2Fsqrt%282%29\" or \"tanA+=+-1%2Fsqrt%282%29\".\r
\n" ); document.write( "\n" ); document.write( "The second instance is unacceptable, since it would situate A outside 0<_A<_90°.
\n" ); document.write( "Thus we have\r
\n" ); document.write( "\n" ); document.write( "\"A+=+tan%5E-1%281%2Fsqrt%282%29%29\".\r
\n" ); document.write( "\n" ); document.write( "Therefore the solution set for the original equation is {0, \"tan%5E-1%281%2Fsqrt%282%29%29\" }
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