document.write( "Question 1015621: 1. Solve for A[0<_A<_90°]
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document.write( "TanA+Tan2A+Tan3A=0 \n" );
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Algebra.Com's Answer #631994 by robertb(5830) You can put this solution on YOUR website! tan A + tan2A + tan3A = 0\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "==> tanA + tan2a = 0 OR \n" ); document.write( "\n" ); document.write( "The first case is equivalent to \n" ); document.write( "This happens only when 3A = 0, or A = 0 degree. (Notice A = 0 does not make the denominator 0, so A = 0 is a valid solution. It can be checked also by using the original equation that A = 0 is indeed a solution.)\r \n" ); document.write( "\n" ); document.write( "The 2nd case \n" ); document.write( "2 - tanA*tan2A = 0. (Notice that this effectively means that the denominator 1 - tanA*tan2A is not equal to 0.)\r \n" ); document.write( "\n" ); document.write( "==> tanA*tan2A = 2 \n" ); document.write( "==> \n" ); document.write( "Now the only value of A that will make the denominator of the last equation 0 is 45 degrees, in which tanA = 1. Thus we exclude A = 45 degrees from the solution and \n" ); document.write( "let \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "The second instance is unacceptable, since it would situate A outside 0<_A<_90°. \n" ); document.write( "Thus we have\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore the solution set for the original equation is {0, |