document.write( "Question 1015625: What's the standard form of the equation of the parabola at\r
\n" ); document.write( "\n" ); document.write( "1.) Vertex at (0, 5), dirextrix is the line x=-2
\n" ); document.write( "2.) Vertex at (6,6), directrix is the line y=7 \n" ); document.write( "
Algebra.Com's Answer #631985 by stanbon(75887)\"\" \"About 
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What's the standard form of the equation of the parabola at
\n" ); document.write( "1.) Vertex at (0, 5), directrix is the line x=-2
\n" ); document.write( "With those conditions the parabola must be opening to the right::
\n" ); document.write( "p = -2
\n" ); document.write( "(y-k)^2 = 4p(x-h)
\n" ); document.write( "(y-5)^2 = -8x
\n" ); document.write( "y^2 - 10y + 25 = -8x
\n" ); document.write( "x = (-1/8)y^2 + (5/4)y - (25/8)\r
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\n" ); document.write( "\n" ); document.write( "2.) Vertex at (6,6), directrix is the line y=7
\n" ); document.write( "With those conditions the parabola must be opening down
\n" ); document.write( "p = 1
\n" ); document.write( "(x-h)^2 = 4*1(y-k)
\n" ); document.write( "(x-6)^2 = 4(y-6)
\n" ); document.write( "x^2-12x+36 = 4y-24
\n" ); document.write( "4y = x^2 - 12x + 60
\n" ); document.write( "y = (1/4)x^2 - 3x + 15
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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