document.write( "Question 1015594: maria is five years older than Ralph. Richard is twice as old as ralph. The sum of the three ages is 65. How old is each \n" ); document.write( "
Algebra.Com's Answer #631966 by robertb(5830)\"\" \"About 
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Let M = age of maria, R = age of Ralph, and \"R%5Bi%5D\" = age of Richard.\r
\n" ); document.write( "\n" ); document.write( "From the 1st sentence, we get M = R + 5.
\n" ); document.write( "From the 2nd sentence, we get \"R%5Bi%5D+=+2R\", and
\n" ); document.write( "from the 3rd sentence, we get \"M+%2B+R+%2B+R%5Bi%5D+=+65\".\r
\n" ); document.write( "\n" ); document.write( "Substituting the first two equations into the 3rd equation, we get\r
\n" ); document.write( "\n" ); document.write( "R + 5 + R + 2R = 65\r
\n" ); document.write( "\n" ); document.write( "4R = 60. ==> R = 15, Ralph's age.\r
\n" ); document.write( "\n" ); document.write( "==> M = R + 5 = 15 + 5 = 20, Maria's age.
\n" ); document.write( "and \"R%5Bi%5D+=+2R\" = 30, Richard's age.\r
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