document.write( "Question 1015597: The sum of the ages of joy and josef now is 69. If josef is twice as old as Joe, how old were they 3 years ago? \n" ); document.write( "
Algebra.Com's Answer #631963 by algebra hello(55)![]() ![]() ![]() You can put this solution on YOUR website! Let Joe's present age=x \n" ); document.write( "then Josef's present age=2x \n" ); document.write( "according to question, \n" ); document.write( "x 2x=69 \n" ); document.write( "3x=69 \n" ); document.write( "x=23 \n" ); document.write( "Joe's age before 3 years= 23-3=20 \n" ); document.write( "Josef's age before 3 years=2*23-3=46-3=43 \n" ); document.write( " |