document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015587>Question 1015587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular garden is 50meters the length of the rectangle is 5metersless than twice the width.find the length and width of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631959 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(L+W)=50\r<BR>\n" );
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document.write( "L=2W-5\r<BR>\n" );
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document.write( "Take the value of L from eq 2 and substitute into eq 1\r<BR>\n" );
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document.write( "2((2W-5)+W)=50\r<BR>\n" );
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document.write( "(2W-5)+W=25\r<BR>\n" );
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document.write( "3W-5=25\r<BR>\n" );
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document.write( "3W=30\r<BR>\n" );
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document.write( "W=10\r<BR>\n" );
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document.write( "L=(2*10)-5 = 15\r<BR>\n" );
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document.write( "W=10 L=15\r<BR>\n" );
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document.write( "Check work  \r<BR>\n" );
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document.write( "Perimeter = 2(L+W) = 2(15+10)= 50 (yes)\r<BR>\n" );
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document.write( "Length (15) is 5 less than twice width (15)  ((2*10)-5) = 10 (yes) </SPAN>\n" );
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