document.write( "Question 1015588: Fractions
\n" );
document.write( "Rewrite descending (decreasing)order.
\n" );
document.write( "(a)2/9,4/5,1/3,3/25,15/16 \n" );
document.write( "
Algebra.Com's Answer #631957 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your fractions are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2/9 \n" ); document.write( "4/5 \n" ); document.write( "1/3 \n" ); document.write( "3/25 \n" ); document.write( "15/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2/9 and 1/3 and 3/25 are less than half so they're going to be smaller than 4/5 and 15/16, so re-order as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2/9 \n" ); document.write( "1/3 \n" ); document.write( "3/25 \n" ); document.write( "4/5 \n" ); document.write( "15/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/3 is equal to 3/9, so 1/3 is bigger than 2/9, so leave them as is.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "compare 3/25 to 2/9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a common multiple will be 9 * 25 = 225.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply 3/25 by 9/9 and multiply 2/9 by 25/25 and you will get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3/25 is equivalent to 27/225 and 2/9 is equivalent to 50/225.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 50 is greater than 27, 2/9 is bigger than 3/25 which means that 3/25 is smaller than 2/9 so reorder your sequence to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2/9 \n" ); document.write( "1/3 \n" ); document.write( "3/25 \n" ); document.write( "4/5 \n" ); document.write( "15/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3/25 \n" ); document.write( "2/9 \n" ); document.write( "1/3 \n" ); document.write( "4/5 \n" ); document.write( "15/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now all you need to do is figure out whether 4/5 is bigger than 15/16 or vice versa.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a common multiple is 5 * 16 = 80.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply 4/5 by 16/16 and multiply 15/16 by 5/5 to get: \n" ); document.write( "4/5 * 16/16 = 64/80 and 15/16 = 75/80. \n" ); document.write( "that says that 15/16 is bigger than 4/5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 15/16 is already below 4/5, your sequence stays the same at:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3/25 \n" ); document.write( "2/9 \n" ); document.write( "1/3 \n" ); document.write( "4/5 \n" ); document.write( "15/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can easily confirm if you did it right by using a calculator and converting all the fractions to decimals.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3/25 = .12 \n" ); document.write( "2/9 = .22..... \n" ); document.write( "1/3 = .33..... \n" ); document.write( "4/5 = .8 \n" ); document.write( "15/16 = .9375\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they're in order.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "however, you were asked to find descending order rather than ascending order.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "all you need to do is reverse the order to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15/16 \n" ); document.write( "4/5 \n" ); document.write( "1/3 \n" ); document.write( "2/9 \n" ); document.write( "3/25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now they're in descending order and you're done.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |