document.write( "Question 1015581: larry Mitchel invested $22,000 advance at 6% annual simple interest and the rest at 2% annual simple interest. if his total yearly interest from both accounts was $1,120 finds the amount invested at each rate \n" ); document.write( "

Algebra.Com's Answer #631953 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+a+\"$ = amount invested @ 6%
\n" ); document.write( "Let $\"+b+\"$ = amount invested @ 2%
\n" ); document.write( "-----------------------------
\n" ); document.write( "(1) $\"+a+%2B+b+=+22000+\"$
\n" ); document.write( "(2) $\"+.06a+%2B+.02b+=+1120+\"$
\n" ); document.write( "-------------------------
\n" ); document.write( "(2) $\"+6a+%2B+2b+=+112000+\"$
\n" ); document.write( "(2) $\"+3a+%2B+b+=+56000+\"$
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) $\"+3a+%2B+b+=+56000+\"$
\n" ); document.write( "(1) $\"+-a+-+b+=+-22000+\"$
\n" ); document.write( "---------------------
\n" ); document.write( " $\"+2a+=+34000+\"$
\n" ); document.write( " $\"+a+=+17000+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+a+%2B+b+=+22000+\"$
\n" ); document.write( "(1) $\"+17000+%2B+b+=+22000+\"$
\n" ); document.write( "(1) $\"+b+=+5000+\"$
\n" ); document.write( "------------------
\n" ); document.write( "$17,000 is invested @ 6%
\n" ); document.write( "$5,000 is invested @ 2%
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+.06a+%2B+.02b+=+1120+\"$
\n" ); document.write( "(2) $\"+.06%2A17000+%2B+.02%2A5000+=+1120+\"$
\n" ); document.write( "(2) $\"+1020+%2B+100+=+1120+\"$
\n" ); document.write( "(2) $\"+1120+=+1120+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );