document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015586>Question 1015586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide 80 into two parts such that 3 times the greater is equal to 2 times the leasser and their sum is 180. Find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631947 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52790)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Divide 80 into two parts such that 3 times the greater is equal to 2 times the leasser and their sum is 180. Find the number<BR>\n" );
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document.write( "\". . . 3 times the greater is equal to 2 times the lesser.\"\r<BR>\n" );
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document.write( "Is it possible?\r<BR>\n" );
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document.write( "Are you sure?\r<BR>\n" );
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document.write( "And which sum is 180? - It is unclear.\r<BR>\n" );
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document.write( "I know what do you mean: 32 and 48.\r<BR>\n" );
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document.write( "But you formulated it incorrectly.\r<BR>\n" );
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