document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015584>Question 1015584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> my question is how do I find the slope,  y-intercept, and the x- intercept  and one additional point on the line. Can you please explain your steps in algebraic vocabulary as I am trying to learn the terminology as well. Please and thanks. \r<BR>\n" );
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document.write( "I know I need to replace y with 0 but kind of lost from there. <BR>\n" );
document.write( "5y=-4\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631945 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the y-intercept is the value of y when x is equal to 0.\r<BR>\n" );
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document.write( "the x-intercept is the value of x when y is equal to 0.\r<BR>\n" );
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document.write( "your equation is 5y = -4.\r<BR>\n" );
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document.write( "put this in slope intercept form and the equation becomes y = -4/5.\r<BR>\n" );
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document.write( "slope intercept form is y = mx + b<BR>\n" );
document.write( "m is the slope<BR>\n" );
document.write( "b is the y-intercept\r<BR>\n" );
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document.write( "the slope is the change in the value of y divided by the change in the value of x.\r<BR>\n" );
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document.write( "when the slope is equal to 0, as it is in the equation of y = -4/5, you will not see the x in the equation.\r<BR>\n" );
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document.write( "if it was there, it would show up as y = 0x - 4/5.\r<BR>\n" );
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document.write( "when the slope is equal to 0, you have a horizontal line.\r<BR>\n" );
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document.write( "when the slope is undefined, you have a vertical line.\r<BR>\n" );
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document.write( "an equation of a vertical line will show up as x = a constant.\r<BR>\n" );
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document.write( "for example:\r<BR>\n" );
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document.write( "y = -4/5 is a horizontal line at y = -4/5.<BR>\n" );
document.write( "x = -4/5 is a vertical line at x = -4/5.\r<BR>\n" );
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document.write( "outside of vertical and horizontal lines, you will see equations in the form of y = mx + b.\r<BR>\n" );
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document.write( "m is the slope.<BR>\n" );
document.write( "b is the y-intercept.\r<BR>\n" );
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document.write( "when you want to find the y-intercept, you replace x with 0 and solve the equation for y.\r<BR>\n" );
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document.write( "when you want to find the x-intercept, you set y = 0 and solve the equation for x.\r<BR>\n" );
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document.write( "your equation is y = -4/5.\r<BR>\n" );
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document.write( "since there is no x in the equation, this means that x can be any value and y will always be -4/5.\r<BR>\n" );
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document.write( "that's a horizontal line.<BR>\n" );
document.write( "it's always at y = -4/5 regardless of what the value of x is.<BR>\n" );
document.write( "this includes when x = 0, therefore, your y-intercept is equal to -4/5.\r<BR>\n" );
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document.write( "graph it and you see a horizontal line on the graph at y = -4/5.\r<BR>\n" );
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document.write( "if you want to find the x-intercept in this equation, you will find that there is no x-intercept.\r<BR>\n" );
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document.write( "since y = -4/5 regardless of the value of x, y will always be -4/5 which means that y can never be equal to 0.\r<BR>\n" );
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document.write( "since y can never be equal to 0, then there is no x-intercept for this equation.\r<BR>\n" );
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document.write( "now let's look at a line that is vertical.\r<BR>\n" );
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document.write( "an equation for a vertical line could be x = -4/5.\r<BR>\n" );
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document.write( "if you look for the y-intercept, there won't be any because the value of x is equal to -4/5 regardless of the value of y.\r<BR>\n" );
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document.write( "since x is always -4/5, it can never cross the y-axis and so you never have a y-intercept.\r<BR>\n" );
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document.write( "if you look for the x-intercept, it will be at x = -4/5 because x is always at -4/5 regardless of the value of y, including y = 0.\r<BR>\n" );
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document.write( "outside of vertical or horizontal lines, you would solve for y-intercept and x-intercept as follows.\r<BR>\n" );
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document.write( "assume the equation is y = -5x + 3.\r<BR>\n" );
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document.write( "to find the x-intercept, set y equal to 0 and solve for x.\r<BR>\n" );
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document.write( "you will get 0 = -5x + 3.<BR>\n" );
document.write( "subtract 3 from both sides of this equation to get -3 = -5x.<BR>\n" );
document.write( "divide both sides of this equation by -5 to get x = -3/-5 which becomes y = 3/5.<BR>\n" );
document.write( "that's your x-intercept.<BR>\n" );
document.write( "the coordinate point of your x-intercept is (3/5,0)\r<BR>\n" );
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document.write( "to find the y-intercept, set x equal to 0 and solve for y.\r<BR>\n" );
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document.write( "you will get y = -5*0 + 3 which becomes y = 3.<BR>\n" );
document.write( "that's your y-intercept.<BR>\n" );
document.write( "the coordinate point of your y-intercept is (0,3).\r<BR>\n" );
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document.write( "the following graph shows you a horizontal line at y = -4/5 and a vertical line at x = -4/5 and the equation of y = -5x + 3 that i just showed you above.\r<BR>\n" );
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document.write( "look below the graph for further comments.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2016/012501.jpg\" alt=\"$$$\" </>\r<BR>\n" );
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document.write( "in this graph:\r<BR>\n" );
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document.write( "blue line is x = -4/5.<BR>\n" );
document.write( "it's a vertical line that intersects the x-axis at x = -4/5 and doesn't intersect the y-axis because it is parallel to the y-axis and will never touch it.\r<BR>\n" );
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document.write( "red line is y = -4/5.<BR>\n" );
document.write( "it's a horizontal line that intersects the y-axis at y = -4/5 and doesn't intersect the x-axis because it is parallel to the x-axis and will never touch it.\r<BR>\n" );
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document.write( "orange line is y = -5x + 3.<BR>\n" );
document.write( "this is the more traditional line.<BR>\n" );
document.write( "it intersects the y-axis at y = 3 and it intersects the x-axis at x = 3/5.\r<BR>\n" );
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document.write( "on the graph, -4/5 shows up as -.8 and x = 3/5 shows up as .6.\r<BR>\n" );
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document.write( "the slope of y = 5x + 3 can be calculated from the x-intercept and the y-intercept as follows:\r<BR>\n" );
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document.write( "the y-intercept is at (0,3)<BR>\n" );
document.write( "the x-intercept is at (.6,0)\r<BR>\n" );
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document.write( "the slope is (y2-y1) / (x2-x1).\r<BR>\n" );
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document.write( "you can assign either of those coordinates to (x1,y1) or (x2,y2).<BR>\n" );
document.write( "the slope will be the same.\r<BR>\n" );
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document.write( "for example:\r<BR>\n" );
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document.write( "x1 = 0 and y1 = 3, while x2 = .6 and y2 = 0.<BR>\n" );
document.write( "(y2-y1)/(x2-x1) becomes (0-3)/.6-0 which becomes -3/.6 which becomes -5.\r<BR>\n" );
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document.write( "if you assign x1 = .6 and y1 = 0, while x2 = 0 and y2 = 3, you will get:<BR>\n" );
document.write( "(y2-y1)/(x2-x1) becomes (3-0)/(0-.6) = 3/-.6 which becomes -5.\r<BR>\n" );
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document.write( "you get the same slope either way.\r<BR>\n" );
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document.write( "you could not find the slope using x and y intercepts for y = -4/5 because that equation has no x-intercept.\r<BR>\n" );
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document.write( "you could not find the slope using x and y intercepts for x = -4/5 because that equation has no y-intercept.\r<BR>\n" );
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document.write( "in those cases, you would need to find another point on the line.\r<BR>\n" );
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document.write( "in y = -4/5, all you need to do is assume any value of x and y will be -4/5 for that value of x.\r<BR>\n" );
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document.write( "in x = -4/5, all you need to do is assume any value of y and x will be at -4/5 for that value of y.\r<BR>\n" );
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document.write( "to find any point on a more standard line, just assume any value for x and then solve for the corresponding value of y.\r<BR>\n" );
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document.write( "here's some references that should be helpful.\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF= \"http://www.purplemath.com/modules/slope.htm\" target = \"_blank\">http://www.purplemath.com/modules/slope.htm</a>\r<BR>\n" );
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document.write( "purplemath has more.<BR>\n" );
document.write( "here's the page that i did the search on.\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF= \"https://www.google.com/?gws_rd=ssl#q=solving+equation+of+straight+lines+purplemath\" target = \"_blank\">https://www.google.com/?gws_rd=ssl#q=solving+equation+of+straight+lines+purplemath</a><BR>\n" );
document.write( "my search was for \"solving equation of straight lines purplemath\"<BR>\n" );
document.write( "take out the \"purplemath\" and you'll get lots of other websites as well.\r<BR>\n" );
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