document.write( "Question 1015578: A passenger trains speed is 60 mi/h, and a freight trains speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make a trip? \n" ); document.write( "
Algebra.Com's Answer #631943 by ikleyn(52873)\"\" \"About 
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\n" ); document.write( "A passenger trains speed is 60 mi/h, and a freight trains speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make a trip?
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document.write( "Let L be the travel distance (now unknown).\r\n" );
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document.write( "Then the passenger train spends \"L%2F60\" hours to cover this distance, while\r\n" );
document.write( "the freight train spends \"L%2F40\" hours.\r\n" );
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document.write( "According to the condition, the difference of these times is 1.5 hour. It gives you an equation\r\n" );
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document.write( "\"L%2F40\" - \"L%2F60\" = 1.5.\r\n" );
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document.write( "Multiply both sides by 40*60 to get off denominators. You will get\r\n" );
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document.write( "60*L - 40*L = 40*60*1.5,   or\r\n" );
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document.write( "20*L = 3600.\r\n" );
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document.write( "Hence, L = \"3600%2F20\" = 180 km.\r\n" );
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document.write( "Then the passenger train spends \"180%2F60\" = 3 hours, while the greight train spends \"180%2F40\" = 4.5 hours.\r\n" );
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document.write( "The problem is solved.\r\n" );
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