document.write( "Question 1015573: Ben starts walking along a path at 2 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 4 mi/h. How long will it be before Amanda catches up to Ben? \n" ); document.write( "

Algebra.Com's Answer #631921 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
What is Ben's head start in miles?
\n" ); document.write( " $\"+d%5B1%5D+=+2%2A1.5+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+3+\"$ mi
\n" ); document.write( "------------------
\n" ); document.write( "Let $\"+d+\"$ = distance Amanda travels
\n" ); document.write( "until she catches up to Ben
\n" ); document.write( "Start a stop watch when Amanda leaves
\n" ); document.write( "Let $\"+t+\"$ = time on stopwatch when
\n" ); document.write( "she catches up with Ben
\n" ); document.write( "---------------------
\n" ); document.write( "Ben's equation
\n" ); document.write( "(1) $\"+d+-+3+=+2t+\"$
\n" ); document.write( "Amanda's equation:
\n" ); document.write( "(2) $\"+d+=+4t+\"$
\n" ); document.write( "----------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) $\"+4t+-+3+=+2t+\"$
\n" ); document.write( "(1) $\"+2t+=+3+\"$
\n" ); document.write( "(1) $\"+t+=+3%2F2+\"$
\n" ); document.write( "She catches up to Ben in 1.5 hrs
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+d+=+4t+\"$
\n" ); document.write( "(2) $\"+d+=+4%2A1.5+\"$
\n" ); document.write( "(2) $\"+d+=+6+\"$ mi
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+d+-+3+=+2t+\"$
\n" ); document.write( "(1) $\"+d+-+3+=+2%2A1.5+\"$
\n" ); document.write( "(1) $\"+d+-+3+=+3+\"$
\n" ); document.write( "(1) $\"+d+=+6+\"$
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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