document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015545>Question 1015545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A dealer has some hard candy worth $2 a pound and some worth $3 a pound. he wishes to make a mixture of 80 pounds that he can sell for $2.20 a pound. how many pounds of each kind should he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631908 by </B><A HREF=/tutors/aboutme.mpl?userid=justasking><B>justasking(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=justasking><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=justasking><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I love these problems.\r<BR>\n" );
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document.write( "Make a picture of buckets. Under one, put \"x\", and in it put $2.<BR>\n" );
document.write( "The second one should have a \"80-x\" under it (you can't have more than 80 pounds of hard candy), and in it write $3.\r<BR>\n" );
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document.write( "The third should have an \"80\" underneath it, and a $2.20 inside the bucket. Put a + between the first two, and a = between the the second and third buckets.\r<BR>\n" );
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document.write( "Now you can make your equation.\r<BR>\n" );
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document.write( "x*2 + 3(80-x)=80*2.20\r<BR>\n" );
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document.write( "2x + 240 - 3x = 176\r<BR>\n" );
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document.write( "2x + 240 = 176 + 3x\r<BR>\n" );
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document.write( "240 = 176 + x\r<BR>\n" );
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document.write( "64 = x\r<BR>\n" );
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document.write( "You need 64 pounds of the $2 candy.\r<BR>\n" );
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document.write( "80 - 64 = 16\r<BR>\n" );
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document.write( "You need 16 pounds of the $3 candy </SPAN>\n" );
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