document.write( "Question 87244: Find the equation of the line.
\n" ); document.write( "Slope -1/3 y-intercept (0,3/2)\r
\n" ); document.write( "\n" ); document.write( "The problem is I do not know how to begin solving it could you give me the steps or an example of this problem with using same method but different numbers.
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Algebra.Com's Answer #63190 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If you want to find the equation of line with a given a slope of \"-1%2F3\" which goes through the point (\"0\",\"3%2F2\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope, and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-3%2F2=%28-1%2F3%29%28x-0%29\" Plug in \"m=-1%2F3\", \"x%5B1%5D=0\", and \"y%5B1%5D=3%2F2\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-3%2F2=%28-1%2F3%29x-%28-1%2F3%29%280%29%29\" Distribute \"-1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3%2F2=%28-1%2F3%29x%2B%281%2F3%29%280%29%29\" Multiply the negatives\r
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\n" ); document.write( "\n" ); document.write( "\"y-3%2F2=%28-1%2F3%29x%2B0\" Multiply \"1%2F3\" and \"0\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F3%29x%2B0%2B3%2F2\"Add \"3%2F2\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F3%29x%2B3%2F2\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-1%2F3\" which goes through the point (\"0\",\"3%2F2\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F3%29x%2B3%2F2\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-1%2F3\" (so this shows our equation has a slope of \"-1%2F3\") and the y-intercept is \"b=3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-1%2F3%29x%2B3%2F2\" (note: if you need help with graphing, check out this solver) and plot the point (\"0\",\"3%2F2\"), we get\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-1%2F3%29x%2B3%2F2\" through the point (\"0\",\"3%2F2\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-1%2F3\" and goes through the point (\"0\",\"3%2F2\"), this verifies our answer.
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