document.write( "Question 1015553: Find 3 consecutive odd integers such that the second integer is 5 times the first integer, the third integer is 100 more than the first integer, and the sum of all 3 integers is 415.\r
\n" ); document.write( "\n" ); document.write( "The equation I have is
\n" ); document.write( "x+5x+100+x=415 and my answers are 45,225,145 \r
\n" ); document.write( "\n" ); document.write( "I'm pretty sure that is incorrect because they aren't consecutive. what is the correct equation and answers? \n" ); document.write( "
Algebra.Com's Answer #631889 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find 3 consecutive odd integers such that the second integer is 5 times the first integer, the third integer is 100 more than the first integer, and the sum of all 3 integers is 415.
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\n" ); document.write( "1st:: 2x-1
\n" ); document.write( "2nd:: 2x+1
\n" ); document.write( "3rd:: 2x+3
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\n" ); document.write( "Note:: The conditions for your equations are contradictory.
\n" ); document.write( "They do not result in a consistent value for \"x\" and therefore
\n" ); document.write( "for the 3 consecutive odd integers.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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