document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015555>Question 1015555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem. I have tried but my answer is incorrect. Show all steps. Thanks in advance\r<BR>\n" );
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document.write( "Put the equation y=x^2&#8722;16x+63 into the form y=(x+h)^2+k:<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631887 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=x^2&#8722;16x+63<BR>\n" );
document.write( "The vertex has an x-value of -b/2a=-(-16)/2=8<BR>\n" );
document.write( "f(8)= -1<BR>\n" );
document.write( "Therefore, the vertex is at (8,-1)<BR>\n" );
document.write( "The vertex form is (x+h)^2 +k, where you change the sign of the x value of the vertex (h) and keep the y component (k)<BR>\n" );
document.write( "y=(x-8)^2 - 1<BR>\n" );
document.write( "Expand that for x^2-16x+64-1<BR>\n" );
document.write( "x^2-16x+63 </SPAN>\n" );
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