document.write( "Question 1015553: Find 3 consecutive odd integers such that the second integer is 5 times the first integer, the third integer is 100 more than the first integer, and the sum of all 3 integers is 415.\r
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document.write( "The equation I have is
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document.write( "x+5x+100+x=415 and my answers are 45,225,145 \r
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document.write( "I'm pretty sure that is incorrect because they aren't consecutive. what is the correct equation and answers? \n" );
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Algebra.Com's Answer #631886 by macston(5194)![]() ![]() You can put this solution on YOUR website! First integer is F. \n" ); document.write( "Second integer must be F+2 (consecutive odd integers) and also 5F. \n" ); document.write( "So \n" ); document.write( "5F=F+2 \n" ); document.write( "4F=2 \n" ); document.write( "F=1/2 \n" ); document.write( "1/2 is not an integer. \n" ); document.write( ". \n" ); document.write( "The third integer must be F+4 (to be consecutive odd) integer and also F+100. \n" ); document.write( "F+4=F+100 \n" ); document.write( "Obviously, this can not happen. \n" ); document.write( ". \n" ); document.write( "There is no solution to this problem as given. \n" ); document.write( " \n" ); document.write( " |