document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015479>Question 1015479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 times another. If the sum of their reciprocals is 2/9, find the two numbers.<BR>\n" );
document.write( "Thank you for any help in solving this problem.<BR>\n" );
document.write( "Daniel H. Jack </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631832 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 3 times another. If the sum of their reciprocals is 2/9, find the two numbers.<BR>\n" );
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document.write( "n is one number<BR>\n" );
document.write( "3n is the other number<BR>\n" );
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document.write( "1/n + 1/(3n) = 2/9<BR>\n" );
document.write( "etc </SPAN>\n" );
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