document.write( "Question 1015473: Hey there, I have recently been set a simultaneous equations hwk that up till now I have found rather easy! My problem occurs at a new type of question I have not been taught about. I will provide 2 questions for reference: \"2x-y%2B1=0\" and \"3x%2B2y%2B4=0\" is the first pair. The 2nd is \"3x-y%2B5=0\" and \"5x%2By-13=0\" is the other pair. I believe that I need to +/-the single integer with no algebraic term, to make it not equal 0, and the rearrange and substitute in. However, when I do this, say with the 2nd, I get \"x=-9\", which I know isn't right, as a friend showed me the answer. But I want to understand how I get there! As the answer is \"x=1\". Thanks for reading and helping me out! \n" ); document.write( "
Algebra.Com's Answer #631824 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
2x - y + 1 = 0
\n" ); document.write( "3x + 2y + 4 = 0
\n" ); document.write( "-------
\n" ); document.write( "4x - 2y + 2 = 0 1st eqn times 2
\n" ); document.write( "3x + 2y + 4 = 0
\n" ); document.write( "--------------------- Add
\n" ); document.write( "7x + 6 = 0
\n" ); document.write( "x = -6/7
\n" ); document.write( "y = 2x + 1 (1st eqn)
\n" ); document.write( "y = -5/7
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\n" ); document.write( "3x - y + 5 = 0
\n" ); document.write( "5x + y - 13 =0
\n" ); document.write( "----------------------- Add
\n" ); document.write( "8x - 8 = 0
\n" ); document.write( "x = 1
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\n" ); document.write( "\n" ); document.write( "---
\n" ); document.write( "y = 8
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