document.write( "Question 1015437: A box contains three drawers. In the first drawer there are 2 gold coins, in the 2nd there are 2 silver coins, and 1 gold coin and 1 silver coin in the 3rd one. A coin is selected at random from a drawer. If the coin selected was a silver, what is the probability that the other coin in that drawer is a gold? \n" ); document.write( "
Algebra.Com's Answer #631796 by FrankM(1040)\"\" \"About 
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Here are the 3 choices -\r
\n" ); document.write( "\n" ); document.write( "Drawer 1 G-G\r
\n" ); document.write( "\n" ); document.write( "Drawer 2 S-S\r
\n" ); document.write( "\n" ); document.write( "Drawer 3 G-S\r
\n" ); document.write( "\n" ); document.write( "You chose S, so there is a 1 in 3 chance the other coin is G.
\n" ); document.write( "Because, you could have S(1) or S(2) or S(3) in your hand, so, respectively, the other coin choices are S(2), S(1), or G(3)\r
\n" ); document.write( "\n" ); document.write( "Once you draw a coin, and see it is silver, you know you've chosen from Drawer 2 or 3. But as I stated, there are now still 3 possibilities, (1) you've chosen the silver coin from drawer 3, (2) you've chosen the first silver coin from drawer 2 or (3) the second silver coin from drawer 2. Only one of these three silver coins sits with the gold coin. \r
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