document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015401>Question 1015401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 ft less than twice it's width. If the perimeter of rectangle is 144 ft find the length and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631763 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L= 2W-3<BR>\n" );
document.write( "2(2W-3)+2W= 144<BR>\n" );
document.write( "4W-6+2W= 144<BR>\n" );
document.write( "4W+2W= 150<BR>\n" );
document.write( "6W= 150<BR>\n" );
document.write( "W= 150/6<BR>\n" );
document.write( "W= 25 The width is 25, and the problem tells us that the length is:<BR>\n" );
document.write( "2(25)-3= 50-3= 47 is the length<BR>\n" );
document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2(47)+2(25)= 144<BR>\n" );
document.write( "94+50= 144 We have the correct answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );