document.write( "Question 1015396: If y(x) = x / 1-x , show that 1/2 [y(x) + y(-x)] = y(x^2) \n" ); document.write( "
Algebra.Com's Answer #631758 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "If y(x) = x / 1-x , show that 1/2 [y(x) + y(-x)] = y(x^2)
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document.write( "y(x) = \"x%2F%281-x%29\",\r\n" );
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document.write( "y(-x) = \"%28-x%29%2F%281-%28-x%29%29\" = \"-x%2F%281%2Bx%29\".\r\n" );
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document.write( "Therefore, \r\n" );
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document.write( "y(x) + y(-x) = \"x%2F%281-x%29\" - \"x%2F%281%2Bx%29\" =    (now write it with the common denominator, which is (1-x)*(1+x) )\r\n" );
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document.write( "= \"%28x%2A%281%2Bx%29%29%2F%28%281-x%29%2A%281%2Bx%29%29\" - \"%28x%2A%281-x%29%29%2F%28%281-x%29%2A%281%2Bx%29%29\" = \r\n" );
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document.write( "= \"%28x+%2B+x%5E2+-+x+%2B+x%5E2%29%2F%281-x%5E2%29\" = \"%282x%5E2%29%2F%281-x%5E2%29\".\r\n" );
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document.write( "Therefore, \r\n" );
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document.write( "\"1%2F2\".\"%28y%28x%29+%2B+y%28-x%29%29\" = \"x%5E2%2F%281-x%5E2%29\".\r\n" );
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document.write( "It is what has to be proved.\r\n" );
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