document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015358>Question 1015358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in triangle ABC, the sum of the measure of angle A and angle B is 90°. Angle A is 30° less than twice angle B. Use this information to find the seasure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631755 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "A=2B-30<BR>\n" );
document.write( "2B-30+B=90<BR>\n" );
document.write( "3B=120<BR>\n" );
document.write( "B=40<BR>\n" );
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document.write( "A=2B-30=2(40)-30=80-30=50<BR>\n" );
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document.write( "A+B+C=180<BR>\n" );
document.write( "50+40+C=180<BR>\n" );
document.write( "C=90<BR>\n" );
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document.write( "ANSWER: A=50; B=40; C=90<BR>\n" );
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document.write( " </SPAN>\n" );
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