document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12349>Question 12349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A consumer goods manufacturer wanted to blend two grades of coffee, one costing $1.50 per kg., the other 200 kg. costing $1.90 per kg., to be sold off at $1.60 per kg. How much coffee costing $1.50 per kg. would be needed?\r<BR>\n" );
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document.write( "This is a new lesson. Please help solve this problem.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6317 by </B><A HREF=/tutors/aboutme.mpl?userid=kusha><B>kusha(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kusha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your problem is wrong and the statement should read to make a mixture costing $1.60 per KG and not to be sold off at 1.60 per kg\r<BR>\n" );
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document.write( "Now this is an alligation question the ratio of cheaper qtty  to dearer qtty can be solved by the formula\r<BR>\n" );
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document.write( "c:d = (d-m)/(m-c)\r<BR>\n" );
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document.write( "c - cheaper qtty(1.5 in this case), d: dearer qtty(1.9 in this case), m: mean qtty(1.6 in this case)\r<BR>\n" );
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document.write( "So c:d = (1.9-1.6)/(1.6-1.5)\r<BR>\n" );
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document.write( "on solving the ratio is 3:1 so if dearer qtty is 1 cheaper qtty is 3<BR>\n" );
document.write( "             thus if dearer qtty is 200 kg, the cheaper qtty should be 600 Kg. </SPAN>\n" );
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