document.write( "Question 1015324: Hello
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document.write( "Help I hope I got the right sign looks like a check mark, trying to multiply and simplify and show my work please.\r
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document.write( " √3x^5√ 18x^6\r
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document.write( "Thanks Betty \n" );
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Algebra.Com's Answer #631695 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i think you want sqrt(3x^5) * sqrt(18x^6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in general, sqrt(a) * sqrt(b) is equal to sqrt(a*b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(4) * sqrt(16) = sqrt(4*16) = sqrt(64) = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(4) = 2 and sqrt(16) = 4 so sqrt(4) * sqrt(16) = 2*4 = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the answers are the same, so sqrt(4) * sqrt(16) = sqrt(4*16)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, your solution becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(3x^5) * sqrt(18x^6) = sqrt(3x^5 * 18x^6) = sqrt(54*x^11) = 3x^5*sqrt(6x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the simplification process went like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(54*x^11) = sqrt(6*9*x^10*x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since sqrt(9) = 3, then the expression becomes 3*sqrt(6*x^10*x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since sqrt(x^10) = x^5, then the expression becomes 3*x^5*sqrt(6x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "why is sqrt(x^10) = x^5?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "because (x^5)^2 = x^(5*2) = x^10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the basic procedure is to remove from under the square root sign, all the perfect squares you can find.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(9) is a perfect square, so you remove it from under the squareroot sign and place it outside the square root sign because sqrt(9) = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(9) = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(9x) = 3sqrt(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the x is not a perfect square so it remains. \n" ); document.write( " \n" ); document.write( " |