document.write( "Question 1015184: Complete the following statement 6a2-5a+1 = (3a-1)(_?_)
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\n" ); document.write( "Daniel H. Jack
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Algebra.Com's Answer #631519 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"6a%5E2-5a%2B1\" .... write \"-5a\" as \"-3a-2a\"
\n" ); document.write( "=\"6a%5E2-3a-2a%2B1\".....group
\n" ); document.write( "=\"%286a%5E2-3a%29-%282a-1%29\"
\n" ); document.write( "=\"3a%282a-1%29-%282a-1%29\"
\n" ); document.write( "=\"%283a-1%29%282a-1%29\"
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