document.write( "Question 1015137: assume that a certain company was producing a bottles of soft drinks it is known that the probablity that the company produce a defective bottles was 0.15.If 10 bottles produced by the company were selected randomly find the probablity that at least two bottles of soft drink is defective? \n" ); document.write( "
Algebra.Com's Answer #631475 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! at least 2 bottles: \n" ); document.write( "find probability of 0, 1. You don't want that, but if you subtract that value from 1, you will get what you do want. \n" ); document.write( "probability of 0 is 0.85^10, because that means all are not defective. \n" ); document.write( "p(0)=0.1969 \n" ); document.write( "p(1)=10 ways it can happen*(0.85^9)(0.15)^1 \n" ); document.write( "=0.3474 \n" ); document.write( "The sum of p(0) and p(1)=0.5443 \n" ); document.write( "At least 2 bottles are defective is 1-0.5443 or 0.4557. \n" ); document.write( "This is easier than computing the nine probabilities from p(2) to p(10), although the last few will be essentially 0. \n" ); document.write( " |